If you have 3 quarters, 5 dimes, and 2 nickels in
your pocket what is the probability you will pick a
dime and then a quarter without putting the dime
back in your pocket?

Step-by-step explanation:

No. Of quarters n(Q)= 3

No. Of dimes n(D) = 5

No. Of nickels n(N) = 2

Total T = 3+5+2 = 10

Prob(D) = n(D)/T = 5/10 = 1/2

Now there are 9 left since it is not replaced back

Prob(Q) = 3/9 = 1/3

Prob(D and Q) = 1/2 × 1/3 = 1/6

where's the diagrams?

the discriminant is 64 + 4*1*12 = 112

this is prime.

step-by-step explanation: