Urn 1 contains 2 white and 4 black balls and urn 2 contains 4 white and 4 black balls. if a ball is drawn at random from one of the two urns, what is the probability that it is a white ball?

Step-by-step explanation:

Given : Urn 1 contains 2 white and 4 black balls and urn 2 contains 4 white and 4 black balls.

Total balls in Urn 1 = 6

Total balls in Urn 2 = 8

Probability of drawing white ball from Urn 1 = P(W |Urn 1) =

Probability of drawing white ball from Urn 2 = P(W |Urn 2)=

Then probability that Urn1 is chosen =P(Urn 1)

Similarly , P(Urn 2)

By Law of total probability :

P(White)= P(W |Urn 1) x P(Urn 1) +P(W |Urn 2) x P(Urn 12)

Hence, the probability that it is a white ball =

its not b

step-by-step explanation:

1. 3.4/4

2. 0.8/7

3. 0.5 x 3

4. 0.9 x 6

5. 10.8

6. 2.35

7. 0.567

8. 9.35

9. 0.02

10. 0.06

11. 0.16

12. 0.42

13. 0.63

14. 5.6

15. 8.1

16. 9.9

17. 0.28

18. 0.48

19. 0.27

20. 0.49

21. 0.45

22. 0.72

23. 0.9

24. 0.88

25. 0.75

26. 0.16

27. 0.328

28. 0.495

29. 0.72

30. 1.068