The frosty ice-cream shop sells sundaes for $2 and banana splits for $3. on a hot summer day, the shop sold 8 more sundaes than banana splits and made $156.

how do you solve this problem?

The shop sold 36 sundaes and 28 banana spilts

Solution:

Let "a" be the number of sundaes sold

Let "b" be the number of banana spilts sold

Cost of 1 sundaes = $ 2

Cost of 1 banana spilt = $ 3

On a hot summer day, the shop sold 8 more sundaes than banana splits and made $156

Therefore,

Number of sundaes sold = 8 + number of banana spilts sold

a = 8 + b ------- eqn 1

Also, given that they made $ 156

Therefore, we frame a equation as:

Number of sundaes sold x Cost of 1 sundaes + number of banana spilts sold x Cost of 1 banana spilt = 156

2a + 3b = 156 ---------- eqn 2

Substitute eqn 1 into eqn 2

2(8 + b) + 3b = 156

16 + 2b + 3b = 156

16 + 5b = 156

5b = 156 - 16

5b = 140

Substitute b = 28 in eqn 1

a = 8 + 28

Thus the shop sold 36 sundaes and 28 banana spilts

4

step-by-step explanation:

6 (donuts) divided by 3 is 2.

so 2/3 means 2 times 2, which is 4/6.

you get two and your friend gets four.