What is the vertex of the quadratic function f(x) = (x-6)(x + 2)?

(2,-16)

Step-by-step explanation:

One way to find the vertex is as follows:

First, we see that the x-intercepts are 6 and -2.

(to see this, we use the fact that the x-intercepts are found by letting y i.e. f(x) = 0. Then we solve each of the factors equal to 0. so i.e.

x-6 = 0

x = 6.

Similarly, x+2 = 0, so x= -2).

Now that we know the x-intercepts, we can use the symmetry property of a quadratic to see the x-coordinate of the vertex occurs mid-way between -2 and 6. So i.e at (6+-2)/2 = 2.

Lastly, we put x = 2 into the equation to find the y-coordinate:

f(2) = (2-6)(2+2) = -4 x 4 = -16.

So the vertex is (2,-16)

7! = 7×6×5×4×3×2

3! = 3× 2

as 7! is multiple of 3! because 7! contains 3! that is 3× 2 as factor

so 7! /(3! ) = 7× 6× 5× 4

= 42 × 20

= 840

its b) 840✌✌✌

dhruv⭐

answer: i believe the answer is e

step-by-step explanation: