Sureepan borrows 40 000 bhat to buy a new computer. the bank charges 7.5% interest compounded yearly. sureepan agrees to pay a half of the amount still owing at the end of each year after the interest has been compounded. determine how much sureepan would have paid back at the end of 4 years.

Explanation:

year 1 (all the values are is $)                                                  

        (including the interest)                     40,000 + 3,000 = 43,000

       (half of the debt)                               43,000 / 2 = 21,500

year 2 (all the values are is $)                                                  

        (including the interest)                     21,500 + 1612.50 = 23,112.50

       (half of the debt)                               23,112.50 / 2 = 11,556.25

year 3 (all the values are is $)                                                  

        (including the interest)                     11,556.25 + 866.72 = 12,422.97

       (half of the debt)                               12,422.97 / 2 = 6,211.48

year 4 (all the values are is $)                                                  

        (including the interest)                     6,211.48 + 465.86 = 6,667.35

       (half of the debt)                               6,667.35 / 2 = 3,338.67                        

Amount paid back at the end of 4 years ($) :

b is 38 degrees.

a is 52 degrees.

this is because if b is 38 and a is 14 degrees more than b than 38+14=52 and 52+38=90 degrees. hope this .