What is the solution to –2(8x – 4) < 2x + 5?

x > x is greater than startfraction 1 over 6 endfraction.
x < x is less than startfraction 1 over 6 endfraction.
x > 6
x < 6

x is greater than StartFraction 1 Over 6 EndFraction.

Step-by-step explanation:

–2(8x – 4) < 2x + 5

⇌  –16x + 8 < 2x + 5

⇌ 3 < 18x

⇌ 1/6 < x

⇌ x > 1/6

true? is that what you're asking or do you mean something else?

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

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