Taxi fares are normally distributed with a mean fare of $22.27 and a standard deviation of $2.20.
(a) which should have the greater probability of falling between $21 & $24;
the mean of a random sample of 10 taxi fares or the amount of a single random taxi fare? why?
(b) which should have a greater probability of being over $24-the mean of 10 randomly selected taxi fares or the amount of a single randomly selected taxi fare? why?

Step-by-step explanation:

Given that taxi Fares are normally distributed with a mean fare of $22.27 and a standard deviation of $2.20.

For a random single taxi std deviation is 2.20

But for a sample of size 10, std deviation would be

This would be less than the 2.20

Because std devition is less for sample we get a big z score for the sample than the single.  

As positive values of z increase we find that probability would decrease since normal curve is bell shaped.

So single taxi fare would have higher probability than sample.

B) Here >24.

By the same argument we have z value less for single taxi hence the probability for more than that would be less than that of sample size 10

step-by-step explanation:

given perimeter: 28cm

length: 9cm

atp,

2(l+w)=p of the reactangle

2(9+x)=28

18+2x=28

2x=28-18

x=10/2

x=5

therefore width is 5 cm