An airline charges the following baggage fees: $25 for the first bag and $35 for the second. suppose 54% of passengers have no checked luggage, 34% have one piece of checked luggage and 12% have two pieces. we suppose a negligible portion of people check more than two bags.
(a) build a probability model, compute the average revenue per passenger, and compute the
corresponding standard deviation.
(b) about how much revenue should the airline expect for a flight of 120 passengers? with what
standard deviation? note any assumptions you make and if you think they are justified.

The average revenue per passenger = E(x) = $15.70

b)$1,884 ± $20

Step-by-step explanation:

a)

Refer  attached fig for probability model,

i)The average revenue per passenger = E(x) = $15.70

Standard Deviation =

ii)  average revenue per passenger = E(x) = $15.70

b) Revenue should the airline expect for a flight of 120 passengers

revenue = 120 * $15.70 = $1,884 ± $20 (or 19.95 rounded up)

use same σ

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this