Express the confidence interval (0.403 comma 0.487 )(0.403,0.487) in the form of modifyingabove p with caretpplus or minus±e. modifyingabove p with caretpplus or minus±eequals=nothingplus or minus±nothing (type an integer or a decimal.)

L = 0.403 is the lower end of the confidence interval

U = 0.487 is the upper end of the confidence interval

The margin of error E is

E = (U-L)/2

E = (0.487-0.403)/2

E = 0.042

Which is half the distance from the lower to upper end

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The midpoint of the confidence interval is the value of (read out as "p hat")

phat = (U+L)/2

phat = (0.487+0.403)/2

phat = 0.445

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The confidence interval (0.403, 0.487) can be rewritten into the form

solution:

as, mean is defined as sum of all the observations divided by total number of observations.

and , median is mid value of the data whether arranged in ascending order or descending order.

consider, roadsters:

2,3,4,5,6,7,8,9

mean =

also, median= , because number of observations is even, so median is mean of two mid values.

now, coming to bandits

2,3,4,5,6

mean =  

median = 4, as number of observations is odd.

so, roadsters has greater median as well mean than bandits.

→option a is true about the repairs performed on 2 types of cars:

bandits have lower median and mean than roadsters.