Fereydoun is conducting a study of the annual incomes of high school teachers in metropolitan areas of fewer than 100,000 population, and in metropolitan areas having greater than 500,000 population.
if computed z value is 16.1, can he conclude that the annual incomes of high school teachers in metropolitan areas having greater than 500,000 population are significantly greater than those paid in areas with fewer than 100,000 population, at 0.05 level of significance?

Yes, the claim can be concluded.

Step-by-step explanation:

We are given the following in the question:

Alpha, α = 0.05

The null hypothesis and alternate hypothesis can be designed in the following manner:

This is a one tailed(right) test.

Now, we calculate the p - value from standard table.

P-value = 0.00001

Since the p value is less than the significance level, we fail to accept the null hypothesis and reject it.

We accept the alternate hypothesis.

Thus, we conclude that there is enough evidence to support the claim that the annual incomes of high school teachers in metropolitan areas having greater than 500,000 population are significantly greater than those paid in areas with fewer than 100,000 population.

you didn't give me the choices, so i will just give you the graph so you can look at your choices and choose the right one.

constant of proportionality = 3 and the equation is c = 3p.

step-by-step explanation:

c = kp   where c = amount of caffeine in mg., p = oz of pepsi and k is the constant of proportionality.

substituting the values given:

24 = 8k

k = 3.

the same value of k will be obtained if we substitute the other given values.