If a jar wrench whose handle extends 17 cm from the center of the jar is attached to the lid, what is the minimum force required to open the jar?

41.5 N

Step-by-step explanation:

Torque is given by:

τ = rF

Solved for force:

F = τ / r

The value of r is the distance from the end of the wrench to the center of the lid, which is:

r = (0.089m / 2) + 0.17m

= 0.2145m

Therefore:

F  = 8.9N∙m / 0.2145m

= 41.5N

is there any photos or whatever?

c) yes, because of asa or aas