The axis of symmetry for the graph of the function f(x) = 3x2 + bx + 4 is x = . what is the value of b?

b = ±i

Step-by-step explanation:

Given the axis of symmetry of the equation f(x) = 3x²+bx+4 is x= b, to get the value of b we will substitute x = b into the equation and equate to zero as shown:

at f(b) = 0

f(b) = 3b² + b(b) + 4 = 0

3b²+b² + 4 = 0

4b² = -4

b² = -4/4

b² = -1

b = √-1

b = ±i

The value of b is a complex number ±i

a c

step-by-step explanation:

you ignore the remainder, therefore the answer is y = x+2

step-by-step explanation:

you have to divide the denominator by the numerator. you can use synthetic division or long division.

[-5] .     1 .     7 .     11

x + 2 + 1/x+5