Adie is rolled n times. what is the probability that at least 1 of the 6 values never apears?

Zero

Step-by-step explanation:

The possible outcomes from rolling a die are 1,2,3,4,5 and 6. The probability of getting one of these numbers when the die is rolled

=1/6 + 1/6 + 1/6 + 1/6 + 1/6 + 1/6

=1

The probability of not getting one of the number plus the probability of getting one of them = 1

Therefore;

probability of not getting one of the number + 1 = 1

probability of not getting one of the number = 0

1) is right

step-by-step explanation:

answer:   35 % is the probability of a late departure or an early arrival.

step-by-step explanation:

let l represents the late departure and e represents the early departure.

then, according to the question,

p(l) = 12 %,   p(e) = 27 % and = 4 %

and, we have to find out,

but, we know that,

which is the required equation that will use to find the probability of a late departure or an early departure.

therefore,   the probability of a late departure or an early arrival =   35 %