Which equation shows a proportional relationship between x and y?

y = 7x/4 and y = 2x/3 are proportional.

Step-by-step explanation:

In a proportional relationship, for any value of one variable, the is a corresponding change in value of the other variable. This means that there is a constant variation between both variables.

Looking at the equations given,

Looking at the equations given,

y = 7x/4

If x = 1, y = 7×1/4 = 1.75

If x = 2, y = 7 × 2/4 = 3.5

If x = 3, y = 7 × 3/4 = 5.25

It is proportional because the constant of variation is 1.75

y = 2x/3

If x = 1, y = 2×1/3 = 0.67

If x = 2, y = 2 × 2/3 = 1.33

If x = 3, y = 2 × 3/3 = 2

If x = 4, y = 2 × 4/3 = 2.67

It is proportional because the constant of variation is 0.67

answer: the dogs need to shift their focus to human scent.

its because the dogs being trained are for search and rescue thus they need to be able to track humans and their specific scent

answer: ratio of volume of cone (with 3 times the height and equal diameter) to volume of cylinder is 2 to 1. the value of π is not used.

step-by-step explanation:

radius is diameter/2 = 4.

area of circle is π r^2.

volume of cylinder is height × area of base = hπr^2 = 3(4^2) π = 48π cubic inches.

not knowing the formula for volume of cone, i calculate it using calculus (which is for calculating things).

volume of cone is integral 0 to h area(y) dy. area(y) is π r(y)^2. r(y) runs r to zero as y runs zero to h, r(0) = r, r(h) = 0.

r(y) = r - r/h y

area(y) = π (r - r/h y)^2 = π (r^2 - 2r^2y/h + r^2y^2/h^2) = π r^2(1-2y/h+y^2/h^2)

antiderivative area(y) = π r^2 (y-y^2/h+y^3/(3h^2))

integral 0 to h = π r^2(h-h^2/h+h^3/(3h^2) - (0)) = π r^2(h - h + h/3) = π r^2(h/3) = π/3 r^2 h

volume of this cone is π/3(4^2)18 cubic inches.

= 6 16 π = 96π cubic inches.

cone has twice the volume, 96/48.

cone height is 6 times the cylinder.

ratio of volume formula: π r^2 cancels.

cone over cylinder ratio is 6h/3 to h, 2 to 1.