The function h(x) is quadratic and h(3) = h(–10) = 0. which could represent h(x)?
h(x) = x2 – 13x – 30
h(x) = x2 – 7x – 30
h(x) = 2x2 + 26x – 60
h(x) = 2x2 + 14x – 60

Any of the choices that would give a value of 0 for h(x) when x is substituted with 3 and -10 should be the answer.

(1)  h(3) = 3² -(13)(3) - 30 = -60        ; h(-10) = (-10)² - (13)(-10) - 30 = 200
(2)  h(3) = 3² – (7)(3) – 30 = -42        ; h(-10) = (-10)² – (7)(-10) – 30 = 140
(3)  h(3) = (2)(3²) + 26(3) – 60 = 36  ; h(-10) =(2)(-10)² + 26(-10) – 60 = -120
(4)  h(3) = (2)(3²) + 14(3) – 60 = 0     ; h(-10) = (2)(-10)² + 14(-10) – 60 = 0

Thus, the answer is the last among the choices. 

Um what? rephrase that ?