Determine the number of possible outcomes when tossing one coin ,two coins ,and three coins then determine the number of possible outcomes for tossing n coins

Number of possible outcome for tossing N coins =

Solution:

Possible outcomes when tossing one coin = {H, T}

Number of possible outcomes when tossing one coin = 2

Possible outcomes when tossing two coins = {HH, HT, TH, TT}

Number of possible outcomes when tossing two coins = 4

Possible outcomes when tossing three coins

                                 = {HHH, HHT, HTH, THH, TTH, THT, HTT, TTT}

Number of possible outcomes when tossing three coins = 8

Therefore, the sequence obtained is .

If continue this sequence, we can obtain number of possible outcome for tossing N coins is .

2 over 5

step-by-step explanation:

the 2: 3 ratio is the length of the ac segment to the cb segment total length. this implies that the ratio between segment ac length and segment ab length is 2: 5. point c is 2/5 from a to b, so the required fraction is 2/5.

y=mx+