Carmen inches of painting and then art contest contest rules say that all paintings must be rectangular with a area no greater than 3003.04 cm commons painting is 16 cm wide what is the greatest length of the painting can have and still have an area with in the contest rules come in inches of painting and then art contest contest rules say that all paintings must be rectangular with a area no greater than 3003.04 cm commons painting is 16 cm wide what is the greatest length of the painting can have and still have an area with in the contest rules

$32,660

step-by-step explanation:

step-by-step explanation:

answer: the answer is 30 miles per hour.

ft/s -> mphmph = ft/s 1.466667mph = 44 divided by 1.466667mph = 30.00000

- r3ktforgood ☕

geometry: triangles

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lessons

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call the larger triangle abc

then the smaller triangle cde is similar to abc (all angles are equal, aaa).  

ab is the side that is 36, and we wish to find de, the side corresponding to ab

area_cde = area_abc - area_cde --> area_abc / area_cde = 2

let x=length of de

ratio of areas = (ratio of sides)^2

+2+=+%2836%2fx%29%5e2+

+2+=+1296%2fx%5e2+

++x%5e2+=+1296%2f2+=+648+

25.45584