The general term for the sequence 3/4,6/5,9/6,12/7,15/8

a. n+3/n+1

b. 3n/3+n

c. 3n/n+1

B .

Step-by-step explanation:

Arithmetic sequence:-

Step1:

Given sequence is

Above sequence taking numerator terms

3,6,9,12,15 are in arithmetic progression

First term a= 3 and difference d = 3

now n t h term of given sequence is

now substitute a =3 and d=3

Step2:-

Above sequence taking denominator

4,5,6,7,8...

here a=4 and d=1

Final answer is the general term of given sequence is