The sales of digital cameras (in millions of units) in year t is given by the function
f(t) = 3.06t + 6.84 (0 ≤ t ≤ 3)
where t = 0 corresponds to the end of 2001. over that same period, the sales of film cameras (in millions of units) is given by
g(t) = −1.85t + 16.48 (0 ≤ t ≤ 3).
(a) show that more film cameras than digital cameras were sold in 2001.
digital cameras
million
film cameras
million

(b) when did the sales of digital cameras first exceed those of film cameras?

Step-by-step explanation:

The function representing the sales of digital cameras (in millions of units) in year t is

f(t) = 3.06t + 6.84 (0 ≤ t ≤ 3)

Also,

The function representing the sales of film cameras (in millions of units) is given by

g(t) = −1.85t + 16.48 (0 ≤ t ≤ 3)

a) where t = 0 corresponds to the end of 2001,

The number of digital cameras sold in 2001 would be

3.06 × 0 + 6.84 = 6.84 digital cameras.

The number of film cameras sold in 2001 would be

−1.85 × 0 + 16.48 = 16.48 film cameras.

Therefore, more film cameras than digital cameras were sold in 2001.

b) 3.06t + 6.84 = −1.85t + 16.48

3.06t + 1.85t = 16.48 - 6.84

4.91t = 9.64

t = 9.64/4.91 = 1.96

Therefore, the sales of digital cameras first exceed those of film cameras at t = 2 and that is in 2003.

idk but i found this "the graph of y = f(x-2) is the graph of y = f(x) translated two units rightward.  

so, since the point (9,2) lies on the graph of y = f(x), the point (11,2) lies on the graph of y = f(x-2)."

step-by-step explanation:

link is

c. y = 1/4 x + 5

step-by-step explanation:

first, put the equation of the line on the graph into slope-intercept form

(y = mx + b):   y = -4x + 8

second, a perpendicular line has to have "an opposite/reciprocal slope" to the original slope. so, find the "m" value in your original equation (it's -4, right? )

original slope: m = -4   perpendicular slope: change the sign to its opposite and find the reciprocal ("flip" the number)

new slope is now positive (b/c the original slope was negative 4), and it's 1/4 (not the original slope of 4 or 4/1)