The difference between two positive numbers is 26 and one number is three times the other. find the numbers.

39 and 13

Step-by-step explanation:

x=3y

y=x-26

substitute: y=3y-26

26+y=3y

26=2y

y=13

substitute: x=3(13)

x=39

13 and 39

Step-by-step explanation:

Represent the numbers by a and b.

Then a - b = the difference between a and b = 26, and

a = 3b.

Now a - b = 26 and a = 3b.  Subbing 3b for a in a - b = 26, we get

3b - b = 26, or 2b = 26.  Thus, b = 13.  Therefore, a = 3(13) = 39.

The smaller number is 13 and the larger is 39.

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b