In a class of 125 students, 27 are computer science majors, 51 are mechanical engineering majors, 12 are civil engineers and the rest are general engineering majors. assume students only have one major.

suppose six students from the class are chosen at random what is the probability none are mechanical engineering majors?

i tried 74/125 * 73/124 * 72/123 * 71/122 * 70/121 * 69/120 * 68/119 but had incorrect answer

There is a 3.95% probability that none are mechanical engineering majors.

Step-by-step explanation:

is the number of different combinatios of x objects from a set of n elements, given by the following formula:

In this problem, we have that:

There are 125 students.

51 of them are mechanical engineering majors and 125-51 = 74 are not mechanical engineering majors.

Suppose six students from the class are chosen at random what is the probability none are mechanical engineering majors?

The total number of students is 125. So total number of 6 student groups is

The total number of non mechanical engineering students is 74. So the total number of 6 non mechanical engineering students is.

The probability is:

The 68/119 ends up simplified in this exercise, this is your mistake.

There is a 3.95% probability that none are mechanical engineering majors.

the correct answer is semicircle

step-by-step explanation:

the answer is semicircle because the shorter arc joining two points on the circumference of a circle is known as the minor arc, the larger arc is called the major arc, and a semicircle is a half circle, formed by cutting a whole circle along a diameter line.

hope i .

the answer is 9.8975

explanation:

when you multiply the "39.59" with the 25% it reduces it and shows its final discounted price. hope this !

step-by-step explanation: