Based on a poll, a newspaper reported that between 52% and 68% of voters would be likely to vote for a schoolbond issue. what is the margin of error of the poll?

The margin of error of the poll is 8%.

Step-by-step explanation:

This is a confidence interval. A confidence interval has both a lower end and an upper end.

The true proportion is the midpoint between the two ends.

The margin of error is the absolute difference between the proportion and the ends(which is the same, upper end - proportion = proportion - lower end),

In this problem, we have that:

The lower end is 52%.

The upper end is 68%.

The proportion is (52 + 68)/2 = 60%.

The margin of error is 60 - 52 = 68 - 60 = 8%.

it has the same slope and a different y-intercept

hope this : )