Given that the side of the square has a length b−a, find the area of one of the four triangles and the area of the small inner square. give the area of one of the triangles followed by the area of the small inner square separated by a comma.

answer: for each 3 girls there is 2 boys . 3: 2

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5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116

i think it would be c

mark brainliest if im right

step-by-step explanation:

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