Write an equation of a line in slope intercept form with slope -3 going through the point (2, -2)

y = - 3x + 4

Step-by-step explanation:

The equation of a line in slope- intercept form is

y= mx + c ( m is the slope and c the y- intercept )

Here m = - 3, thus

y = - 3x + c ← is the partial equation

To find c substitute (2, - 2) into the partial equation

- 2 = - 6 + c ⇒ c = - 2 + 6 = 4

y = - 3x + 4 ← equation of line

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐