After leaving the runway, a plane's angle of ascent is 15 degrees and its speed is 272 feet per second. how many minutes will it takefor the airplane to climb to a height of 14,000 feet? round anwer to two decimal places.

Step-by-step explanation:

Angle with horizontal = 15°

Velocity of plane = 272 feet per second angle of ascent is 15 degrees

Velocity of plane = 272 cos 15 i + 272 sin 15 j = 262.73 i + 70.40 j ft/s

Vertical velocity = 70.40 ft/s

Vertical displacement = 14000 ft

We have

      Vertical displacement = Vertical velocity x Time

      14000 = 70.40 x Time

      Time = 198.87 seconds = 3.31 minutes

It takes 3.31 minutes the airplane to climb to a height of 14,000 feet

(x+3)(x+7)

step-by-step explanation:

answer is c

step-by-step explanation:

81/12=324/x

x=48