There is an international tennis tournament at your local stadium and gemma has been selected to work as a ball girl.

out of 225 applicants, 1 5 were successful.

of the successful applicants, 20% couldn’t make all the training sessions and were discounted.

how many were selected to work at the tournament?

45 applicants were selected to work in the international tennis tournament at your local stadium, but just 36 (Gemma included) completed all the training sessions.

Step-by-step explanation:

1. Let's review the information provided to us to answer the question correctly:

Number of applicants to work in the international tennis tournament = 225

Number of successful applicants = 1/5 of 225

Number of successful applicants that couldn't make all the training sessions and were discounted = 20%

2. How many selected to work at the tournament?

For answering this question, we will make the following calculations:

Number of successful applicants = 1/5 of 225 (1/5 = 0.2)

Number of successful applicants = 225 * 0.2

Number of successful applicants = 45

Number of successful applicants that couldn't make all the training sessions and were discounted = 20% of 45

Number of successful applicants that couldn't make all the training sessions and were discounted = 0.2 * 45 = 9

45 applicants were selected to work in the international tennis tournament at your local stadium, but just 36 (Gemma included) completed all the training sessions.

chase is right because he already been to the swings and he know how far it will be to get there

step-by-step explanation:

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v