Acertain system can experience three different types of defects. let ai (i = 1,2,3) denote the event that the system has a defect of type i. suppose that the following probabilities are true.
p(a1) = 0.12 p(a2) = 0.08 p(a3) = 0.05
p(a1 ? a2) = 0.14 p(a1 ? a3) = 0.14
p(a2 ? a3) = 0.11 p(a1 n a2 n a3) = 0.01
(a) given that the system has a type 1 defect, what is the probability that it has a type 2 defect? (round your answer to four decimal places.)

(b) given that the system has a type 1 defect, what is the probability that it has all three types of defects? (round your answer to four decimal places.)

(c) given that the system has at least one type of defect, what is the probability that it has exactly one type of defect? (round your answer to four decimal places.)

(d) given that the system has both of the first two types of defects, what is the probability that it does not have the third type of defect? (round your answer to four decimal places.)

70

step-by-step explanation:

2*5=10

4*15=60

60+10=

70

the diameter is 16 cm. are you a teacher?

step-by-step explanation:

move it to the other side

step-by-step explanation:

step-by-step explanation:

i found the life tables for the year 2012. 

life table of males at age 30. probability of dying between ages x and x+1

total population:  

29–30 . . . . . . . . . . . . 0.001030

30–31 . . . . . . . . . . . . 0.001061

males:  

29–30 . . . . . . . . . . . . 0.001420

30–31 . . . . . . . . . . . . 0.001448

white population

29–30 . . . . . . . . . . . . 0.001005

30–31 . . . . . . . . . . . . 0.001037

white males

29–30 . . . . . . . . . . . . 0.001372

30–31 . . . . . . . . . . . . 0.001399

non hispanic white population

29–30 . . . . . . . . . . . . 0.001083

30–31 . . . . . . . . . . . . 0.001116

non hispanic white males

29–30 . . . . . . . . . . . . 0.001477

30–31 . . . . . . . . . . . . 0.001503

jacob, non hispanic white male. 30 years old.

probability that jacob lives to be 30 years old. 

since the given probabilities are probabilities of dying, i think we simply subtract it from 1 to get the probability of living. we will use the probability of non hispanic white male.

                                          probability of living to be 30 y.o.

29 - 30 : 1 - 0.001477 = 0.998523

30 - 31 : 1 - 0.001503 = 0.998497