3. the angles of elevation to an airplane from two points a and b on level ground are 55o and 72o respectively. a and b are 2.2 miles apart and the plane is east of both points. find the altitude of the plane.

CD = 5.9 mi

Step-by-step explanation:

Given:

∠DAC = 55°

∠DBC = 72°

AB = 2.2 mi

∠ABD = 180 - ∠DBC = 180 - 72 = 108°

∠ADB = 180 - ∠BAD - ∠ABD = 180 -55 - 108 = 17°

Using Sine Rule:

Solving for BD:

BD = 6.2 mi

From ΔBDC

Sin(72) = CD / BD

Sin(72) = CD / 6.2

Solving for CD:

CD = 6.2*sin(72) = 5.9 mi

the answer is 13

step-by-step explanation:

5*5=25

12*12=144

25+144=169

169^2=13

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