Of 375 randomly selected medical students, 30 said that they planned to work in a rural community. find a 95% confidence interval for the true population proportion of all medical students who plan to work in a rural community.

(0.05256, 0.10744) .

Step-by-step explanation:

We know that the confidence interval for population proportion is given by :-

  (1)

, where = Sample proportion

n= Sample size

z* = Critical z-value.

Let p be the population proportion of all medical students who plan to work in a rural community.

As per given , we have

n= 375

Critical z-value for 95% confidence interval = 1.96

Put all values in (1) , we get

Hence, the 95% confidence interval for the true population proportion of all medical students who plan to work in a rural community is (0.05256, 0.10744) .

75

step-by-step explanation:

you do x-29=46 (the number of cantaloupes sold)

in order to find x, you have to find what minus 29 equals 46, meaning you'd have to add 29 to 46.

29+46=75

if you replace x with 75, the equation looks like:

75-29=46

x=75

the answer is 21%.