Eights rooks are placed randomly on a chess board. what is the probability that none of the rooks can capture any of the other rooks? translation for those who are not familiar with chess: pick 8 unit squares at random from an 8 × 8 square grid. what is the probability that no two chosen squares share a row or a column? hint. you can think of placing the rooks both with or without order, both ap- proaches work.

Step-by-step explanation:

There are only 2 solutions for none of the rooks can capture any of the other rooks: only if they are laid out in either of the 2 diagonal of the chess board

The number of possible combination for the rock to laid out in 8x8 (64 slots) chess board

possible combination

So the probability is pretty thin

y = 5x + 17

step-by-step explanation:

a perpendicular line will be the opposite reciprocal slope of the given equation.   the slope given is -1/5 so the opposite reciprocal is 5

find b:

7 = 5 (-2) + b

7 = -10 + b

17 = b

write equation

y = 5x + 17

b because it contains 40% of the possible results from the random list.  

0,1,2,3 v 4,5,6,7,8,9  

4 integers to 6 integers  

40% success vs 60% fail

step-by-step explanation: