In a random sample of 70 people, it was found that 44 of them were fans of the new york yankees. what is the margin of error for the true proportion of all individuals who are fans of the new york yankees? . a. 0.0088 . b. 0.058. c. 0.063. d. 0.116. e. 0.173

The general formula for the margin of error would be:

z * √[p (1-p) ÷ n]

where:
z = values for selected confidence level
p = sample proportion
n = sample size

Since the confidence level is not given, we can only solve for the 
√[p (1-p) ÷ n]  part.

p = 44/70
n = 70

√[44/70 (1 - (44/70) ÷ 70]

√[0.6286 (0.3714)] ÷ 70

√0.2335 ÷ 70

√0.0033357 = 0.05775 or 0.058 Choice B.

Yuh yeet honestly idk