which pair of functions is not a pair of inverse functions?

a. f(x)= x+1/6 and g(x)= 6x-1

b. f(x)= x-4/19 and g(x)= 19x+4

c. f(x)= x5 and g(x)= 5√x

d. f(x)= x/x + 20 and g(x)= 20x/x-1
you!

Option in D is not an inverse function.

Step-by-step explanation:

A. Say,

⇒ 6y = x + 1

⇒ x = 6y - 1

Here, g(x) = 6x - 1, if g(x) is the inverse function of f(x).

B. Let us assume,

⇒ 19y = x - 4

⇒ x = 19x + 4

If g(x) is the inverse function of f(x), then, g(x) = 19x + 4

C. Let

⇒

Here, , if g(x) is the inverse function of f(x).

D. Let

⇒ yx + 20y = x

⇒ x(y - 1) = - 20y

⇒

Now, if g(x) is the inverse function of f(x), then,

Therefore, option in D is not an inverse function. (Answer)

question

what is the value of the third quartile of the data set represented by this box plot? a. 19 b. 21 c. 26 d. 29

answer

c