Aπ_ ("pi-minus") particle, which has charge -e, is at location ‹ 6.00 10-9, -2.00 10-9, -3.00 10-9 › m. what is the electric field at location < -5.00 10-9, 5.00 10-9, 4.00 10-9 > m, due to the π_ particle? an antiproton (same mass as the proton, charge -e) is at the observation location. what is the force on the antiproton, due to the π-? expert answer

the simplified form is

step-by-step explanation:

we want to simplify the expression,

let us change the middle bar to a normal division sign to obtain,

we multiply the first fraction by the reciprocal of the second fraction to obtain,

we factor to obtain,

we cancel the common factors to get,

we simplify to get,

the correct answer is b

to find the perimeter, you add up all the lengths of the sides. in this case you would have to add up 18+22+40+80 which equals 160.

option b  

step-by-step explanation:

we know that

the distance from point n to lm in the figure is equal to the distance of the perpendicular line to lm that passes through the point n

so

the distance is equal to the segment no

> given problem

therefore

the distance from point n to lm is equal to