Question
solve the problem by multiplying first.
a clothing store is having a sale on shirts and jeans. four shirts and two pairs of jeans cost $68. three
s 4s + 2) = 68
shirts and three pairs of jeans cost $81. the system of equations 3s + 3) = 81 models this
situation, where s is the cost of a shirt and is the cost of a pair of jeans. how much does one shirt an
one pair of jeans cost?
one shirt costs
and one pair of jeans cost $
.

A shirt cost $7 and a jean cost $20

From the question given, we have already been given the equations which are:

4s + 2j = 68 equation i

3s + 3j = 81 equation ii

Multiply equation i by 3

Multiply equation ii by 4

12s + 6j = 204 equation iii

12s + 12j = 324 equation iv

Subtract iii from iv

6j = 120

j = 120/6

j = 20

A jean cost $20

We can then calculate the value of the shirt and this will be:

4s + 2j = 68

4s + 2(20) = 68

4s + 40 = 68

4s = 68 - 40

4s = 28

s = 28/4

s = 7

A shirt cost $7

Therefore, a shirt cost $7 and a jean cost $20

Read related link on:

link

Step-by-step explanation:

4s + 2j = 682j = -4s + 68j = -2s + 34

3s + 3j = 81

3s + 3(-2s + 34) = 81

3s - 6s + 102 = 81

3s - 6s = 81 - 102

-3s = - 21

s = -21/-3

s = 7 < shirts cost 7 bucks

j = -2s + 34

j = -2(7) + 34

j = -14 + 34

j = 20 < jeans cost 20 bucks

you didn't post any answer choices, so its not 100% clear what your teacher is looking for

however, log(15/7) is equivalent to log(15) - log(7)

i'm using the rule log(x/y) = log(x) - log(y)

51840000 cm 2

step-by-step explanation: