Mis the midpoint of segment vw. vm is 4x-1 and mw is 3x+3. find the value of x.

The value of x = -7/2

Since M is the midpoint of VW and VM = 4x - 1 and MW = 3x + 3, it implies that

MW = VM/2

So, 3x + 3 = (4x - 1)/2

cross-multiplying, we have

2(3x + 3) = 4x - 1

Expanding the bracket, we have

6x + 6 = 4x - 1

Subtracting 4x from both sides, we have

6x - 4x + 6 = 4x - 4x - 1

2x + 6 = - 1

Subtracting 6 from both sides, we have

2x + 6 - 6 = -1 - 6

2x = -7

Dividing through by 2, we have

x = -7/2

So, the value of x = -7/2

Learn more about midpoint of a segment here:

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x=4

Step-by-step explanation:

Because M is the midpoint of VW both segments VM and MW are created as EQUALS because VW is cut in half to make these segments. Since the length of VM and MW are equal then you can use the equation 4x-1=3x+3. First add one on both sides which will give you the equation 4x=3x+4. Lastly you want to isolate x by subtracting 3x on both sides to then get x=4

explanation:

previous steps have made pa≅ pb ≅ st ≅ su. setting the compass width to ab allows you to make tu the same length. then δstu ≅ δpab by the sss congruence postulate, and ∠p ≅ ∠s by the reason cpctc.