A. startroot startfraction 2 (2) (3) (3) (a) (a) (a) (a) (a) (a) (a) (a) over 3 (3) (5) (5) (a) (a) endfraction endroot
b. startroot startfraction 4 a superscript 6 baseline over 25 endfraction endroot
c. startfraction 5 over 25 endfraction startroot startfraction a superscript 8 over a squared endfraction endroot
d. startfraction 6 over 15 endfraction a superscript 4
e. two-fifths a cubed
which expressions listed on the left are equivalent to startroot startfraction 36 a superscript 8 baseline over 225 a squared endfraction endroot? check all that apply. (assume that a ≠ 0.)
a
b
c
d
e

Option A. StartRoot StartFraction 2 (2) (3) (3) (a) (a) (a) (a) (a) (a) (a) (a) Over 3 (3) (5) (5) (a) (a) EndFraction EndRoot

Step-by-step explanation:

From all the five options, we need to find the expression which is equivalent to

Option A: "StartRoot StartFraction 2 (2) (3) (3) (a) (a) (a) (a) (a) (a) (a) (a) Over 3 (3) (5) (5) (a) (a) EndFraction EndRoot" which can be written as

Hence, Option A is the correct answer.

Option B: "StartRoot StartFraction 4 a Superscript 6 Baseline Over 25 EndFraction EndRoot" which can be written as

which is not equivalent to

Hence, Option B is not the correct answer.

Option C: "StartFraction 5 Over 25 EndFraction StartRoot StartFraction a Superscript 8 Over a squared EndFraction EndRoot" which can be written as

which is not equivalent to

Hence, Option C is not the correct answer.

Option D: "StartFraction 6 Over 15 EndFraction a Superscript 4" which can be written as

which is not equivalent to

Hence, Option D is not the correct answer.

Option E: "Two-fifths a cubed" which can be written as

which is not equivalent to

Hence, Option E is not the correct answer.

Hence, the correct option is A.

Thus, the expression is equivalent to StartRoot StartFraction 2 (2) (3) (3) (a) (a) (a) (a) (a) (a) (a) (a) Over 3 (3) (5) (5) (a) (a) EndFraction EndRoot.