Is appreciated with the question that is in the image below

x = ±i, x = -3, and x = -1

Step-by-step explanation:

If x = -1 is a solution, then x + 1 is a factor.  Using grouping:

x⁴ + 4x³ + 4x² + 4x + 3 = 0

x⁴ + 4x³ + 3x² + x² + 4x + 3 = 0

x² (x² + 4x + 3) + x² + 4x + 3 = 0

(x² + 1) (x² + 4x + 3) = 0

(x² + 1) (x + 3) (x + 1) = 0

All the solutions are x = ±i, x = -3, and x = -1.

a) one student is chosen from classroom a, then a student is chosen from classroom b.  

step-by-step explanation:

independent events are ones in which the probability of one event does not affect the probability of the second event.

one student is chosen from classroom a; this does not affect the chances of choosing a student from classroom b.   this makes these independent events.

when one card is chosen from a standard deck and then set aside before a second card is chosen, the probability of the second card being chosen changes.   this makes them dependent events.

when one student is chosen from classroom a and then a second student is chosen from classroom a, the probability of choosing the second student changes.   this makes them dependent events.

when a letter is chosen from the alphabet and then a second letter is chosen, the probability of choosing the second letter changes.   this makes them dependent events.