a(n) = - 4+ (n - 1)(6)

find the third, fourth and, eleventh terms of the sequence described by the rule

a(3)=

a(4)=

a(11)=

i will give brainlest ❤️❤️

answers in steps

Step-by-step explanation:

if A(n) = - 4+ (n - 1)(6) means A(n) = - 4+ (n - 1) x 6

A(3) = - 4+ (3 - 1) x 6 = 8

A(4) = - 4+ (4 - 1) x 6 = 14

A(11) = - 4+ (11 - 1) x 6 = 56

if A(n) = - 4+ (n - 1)(6) means A(n) = - 4+ (n - 1)⁶

A(3) = - 4+ (3 - 1)⁶ = - 4 + 64 = 60

A(4) = - 4+ (4 - 1)⁶ = - 4 + 6561 = 6557

A(11) = - 4+ (11 - 1)⁶ = - 4 + 1000000 = 999996

1. is 4 and 2. is 3

step-by-step explanation:

so if you look at the first one you see that 1 is to 4 and 2 is to 8 and so on, so you can see for every 1 there is a times 4 so if it were 3 then it would be 3*4 and it is 12

for number 2 it is 3 because 1 is to 3 and 2 is to 6 so for every 1 there is 3 so if it were 3 then there would be 3*3 = 9

answer: 800

step-by-step explanation: