Acylindrical tank of radius 5 ft and height 9 ft is two-thirds filled with water. find the work required to pump all the water over the upper rim.

130.826 kilojoules

Step-by-step explanation:

The Work required to pump water = pgV

Where, p = density of water = 1000 kg/m³

g = acceleration due to gravity = 9.81ms-¹

V = volume of water

Since, radius r = 5 ft and height h = 9ft

Volume of water in the cylindrical tank = (2/3)πr²h

V = (2/3)π *5²*9 = 471.24 ft³ = 471.24 * 0.0283m³ = 13.336m³

Work required = 1000*9.81*13.336

W = 130.826 KJ

Therefore, the work required to pump water 2/3 of the volume of the cylindrical tank = 130.826 kilojoules.

because linear equations are a lot simpler than quadratics equations, and linear equations formula is a lot easier to memorize. that's why i think they're harder.

answer: need a picture

step-by-step explanation: