Abox contains 5 plain pencils and 5 pens. a second box contains 3 pencils and 1 crayon. one item from each box is chosen at random what is the probability that a pen from the first box and a crayon from the second box are selected

0.75

Step-by-step explanation:

OK maths is always about looking at thing simply, one by one.

Let us look at the first box. There r 5 pencils and 5 pens. So what is the probability of getting a pen from first box? First there r total of 10 things in the first box. Probability of getting a pen from that box? It is 5÷10 which is number of favorable pitcomes to pen ÷ total number of outcomes which is 10.

Now the second box. There r 1 crayon and 3 pencils. Total of 4 outcomes(3plus1).

So probablilty of getting a crayon from second box is number of favorable outcomes to crayon ÷ total number of outcomes which is 4=1÷4

Now add the first probability of getting a pen from first box and probability of getting a crayon from second box. This is because it's given in the question to find out the probability of getting a pen AND a crayon which means first find the probability of pen and crayon seperatly and then add them.

Now add those 2 probabilities together which is 5÷10 plus 1÷4 then we will get 0.75.

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75 tickets have been sold so far.

step-by-step explanation:

in this question it is clearly mentioned that 45 children's tickets have been sold and this number is 60% of the total tickets sold.

now let's assume the total number of tickets sold be x.

then 60% of x = 45

⇒

⇒ x(.6) = 45

by dividing with .6 on both the sides of the equation

⇒ x = 75

therefore 75 tickets have been sold so far.

56.6

step-by-step explanation:

the ratio of the perimeters is equal to the scale.

the ratio of the areas is equal to the square of the scale.

34 / 20 = k

a / 19.6 = k²

substituting:

a / 19.6 = (34 / 20)²

a = 19.6 (34 / 20)²

a ≈ 56.6