The equation of line ab is y = 2x + 4. what is the equation of a line parallel to line ab in slope-intercept form that contains the point (3,-2)?
oy = 2x - 4
oy=-*
oy = 2x - 8

Step-by-step explanation:

eq. of line parallel to AB is y=2x+a

if it passes through (3,-2) then

-2=2×3+a

a=-2-6=-8

y=2x-8

y = 2x - 8

Step-by-step explanation:

The equation of a straight line can be represented in the slope intercept form as

y = mx + c

Where

m = slope = (change in the value of y in the y axis) / (change in the value of x in the x axis)

The equation of the given line, AB is

y = 2x + 4

Comparing with the slope intercept form, slope = 2

If two lines are parallel, it means that they have the same slope. Therefore, the slope of the line passing through (3, -2) is 2

To determine the intercept, we would substitute m = 2, x = 3 and y = -2 into y = mx + c. It becomes

- 2 = 2×3 + c = 6 + c

c = - 2 - 6 = - 8

The equation becomes

y = 2x - 8

i used to know how to do this in 7th but i forget easily

step-by-step explanation: