Find the distance from the point (-4, -1, -3) to the (a) xy-plane (b) yz-plane (c) xz-plane.

(a) Distance from the point (-4, -1, -3) to the xy-plane is 3.

(b) Distance from the point (-4, -1, -3) to the yz-plane is 4.

(c) Distance from the point (-4, -1, -3) to the xz-plane is 1.

Step-by-step explanation:

If a point is defined as P(x,y,z), then the distance of point P,

1. From xy-plane = |z|

2. From yz-plane = |x|

3. From xz-plane = |y|

The given point is (-4, -1, -3). Here, x=-4, y=-1 and z=-3.

Distance from the point (-4, -1, -3) to the xy-plane is

Distance from the point (-4, -1, -3) to the yz-plane is

Distance from the point (-4, -1, -3) to the xz-plane is

a). Distance from x-y plane = 3 units.

b). Distance from y-z plane = 4 units.

c). Distance from x-z plane = 1 unit.

Step-by-step explanation:

Coordinates of a point have been given as (-4, -1, -3).

Polar coordinates of any point represent the its distance from every individual plane (y-z plane, x-z plane, x-y plane).

Now we can find

a). Distance of the point from x-y plane will be the value of z-coordinate

= 3 units

b). Distance of this point from y-z plane = x coordinate

= 4 units

c). Distance of the point from x-z plane = y coordinate

= 1 unit.

i'm sorry i don't know

step-by-step explanation:

asdsad

step-by-step explanation: