Mathematics, 17.01.2020 02:31 Alex4530

Blood pressure values are often reported to the nearest 5 mmhg (100, 105, 110, the actual blood pressure values for nine randomly selected individuals are given below. 118.6 127.4 138.4 130.0 113.7 122.0 108.3 131.5 133.2a. what is the median of the reported blood pressure values? b. suppose the blood pressure of the second individual is 127.6 rather than 127.4 (a small change in a single value). howdoes this affect the median of the reported values? what does this say about the sensitivity of the median to rounding orgrouping in the data

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Answer from: londonval

a) And the value on the fifth position is Median=127.4

b) Since we have the same sample size the position for the median would be the 5th on the dataset ordered, and for this case the Median=127.6

The median on this case was affected by the change of one value.

The median is not affected by outliers for this case this measure is a rubusteness estimator compared to the sample mean that is very affected by outliers.

When we have rounding or grouping, the median can be hoghly sensitive to small changes.

Step-by-step explanation:

The median by dfinition is "the middle number in a sorted, ascending or descending, list of numbers and can be more descriptive of that data set than the average".

For this case we have the following datsaset:

118.6 127.4 138.4 130.0 113.7 122.0 108.3 131.5 133.2

The first step on this case is sort the data on increasing order, and after do this we got:

108.3, 113.7, 118.6,122, 127.4,130,131.5,133.2,138.4

Part a

For this case since we have a sample size of n =9 and is and odd number we the median would be on the following position from the data ordered:

$\frac{n+1}{2} =\frac{9+1}{2}=5$

And the value on the fifth position is Median=127.4

Part b

For this case we have the following dataset with the change:

118.6 127.6 138.4 130.0 113.7 122.0 108.3 131.5 133.2

And after order the data we got:

108.3, 113.7, 118.6,122, 127.6,130,131.5,133.2,138.4

And again since we have the same sample size the position for the median would be the 5th on the dataset ordered, and for this case the Median=127.6

The median on this case was affected by the change of one value.

The median is not affected by outliers for this case this measure is a rubusteness estimator compared to the sample mean that is very affected by outliers.

When we have rounding or grouping, the median can be hoghly sensitive to small changes.

Answer from: Quest

function 2 has a greater rate of change than function 1

function 2 has a greater y-intercept than function 1

step-by-step explanation:

$\newline{\text{the rate of change is change per unit time}}$ $\newline{\text{for (x,y), rate of change is }\frac{y_2-y_1}{x_2-x_1} \text{ or change in y divided by change in x}}$ $\newline{\text{for function 1, the cost goes up by 75-45=30 each time every hour}}$ $\newline{\text{that means that the slope of function 1 is 30 per hour}}$ $\newline{\text{for the 2nd function, 40 is added every hour. therefor, the slope is 40 per hour}}$ $\bigskip\newline{\text{since 40 per hour> 30 per hour, function 2 has a greater rate of change than function 1}}$ $\bigskip\newline{\text{the y intercept is the y value when x is 0}}$ $\newline{\text{for function 1, the y value when x is 0 is 45}}$ $\newline{\text{for function 2, the y value when x is 0 (or the flat rate) is 50}}$ $\newline{\text{since 50> 45, function 2 has a greater y intercept than funciton 1}}$ $\bigskip\bigskip\newline{\text{the answers are: }}$ $\newline{\text{ function 2 has a greater rate of change than function 1}}$ $\newline{\text{function 2 has a greater y-intercept than function 1.}}$

Answer from: Quest

step-by-step explanation:

ask goog great chance of finding the solution there

Given: b is the midpoint of ac and d is the midpoint of ce. prove: bd || ae

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Blood pressure values are often reported to the nearest 5 mmhg (100, 105, 110, the actual blood pre...