Anjali’s school is selling tickets to the annual dance competition on the first day of ticket sales the school sold 6 adult tickets and 8 student tickets for a total of $130 the school took in $90 on the second day by selling 2 adult tickets and 12 student tickets find the price of an adult ticket and the price of a student ticket

Adults = 15$

Students = 5$

Step-by-step explanation:

First, to solve this problem, you have to make two equations.

I would check to make sure it would work for both equations.

1st equation

6x+8y= 130$

2nd equation

2x+12y= 90$

x= adults

y= students

Solve For X on the second equation

2x=90-12y

x=45-6y

Then you plug x to the next equation

6(45-6y)+8y=130

270-36y+8y=130

-28y=-140

28y=140

y=5

If you plug that for the second equation, it will be:

2x+60=90

2x=30

x=15

Hope this Helps!!

See https://web2.0calc.com/questions/help_85170.

the answer would be 484

step-by-step explanation:

just multiply 0.484 times 1,000 (formula)

correct choice is b

step-by-step explanation:

when you calculate the average rate of change of a function, you are finding the slope of the secant line between the two points. for the function the average rate of change from point to point can be calculated as

to find the average rate of change from day 2 to day 10, note that at day 2, 8 houses were sold, so a(2,8) and at day 10, 2 houses were sold, so b(10,2). thus,