18. use the given degree of confidence and sample data to find a confidence interval for the population standard deviation. assume that the population has a normal distribution. round feet confidence interval limits to the same number of decimal places as the sample standard deviation.
weights of men: 90% confidence; n=14, x=161.0 lb, s=10.9 lb
i know the answer but i need with the steps

8.3 < σ < 16.2

Step-by-step explanation:

The population variation can be estimated between:

(n−1) s² / χ²α/2 < σ² < (n−1) s² / χ²(1−α/2)

At 90% confidence and 13 degrees of freedom, χ²α/2 = 22.4 and χ²(1−α/2) = 5.89.

(14−1) 10.9² / 22.4 < σ² < (14−1) 10.9² / 5.89

69.0 < σ² < 262.2

8.3 < σ < 16.2

1/3

step-by-step explanation:

to find this, you can divide 12 by 4 which is 3 or you can multiply 4 until you reach 12 (4x3=12). both should give you 3, meaning theres three times less bananas than there are oranges.