14. use the given degree of confidence and sample data to construct a confidence interval for the population mean. assume that the population has a normal distribution.
n=10, x=8.7, s=3.3, 95% confidence
i know the answer is 6.34< μ< 11.06 but i dont know how to get there

Step-by-step explanation:

Confidence interval = mean ± margin of error

CI = μ ± ME

The mean is μ = 8.7.

Margin of error = critical value × standard error

ME = CV × SE

At 95% confidence and 9 degrees of freedom, CV = 2.262.

SE = s / √n

SE = 3.3 / √10

SE = 1.04

The margin of error is:

ME = 2.262 × 1.04

ME = 2.36

CI = 8.7 ± 2.36

CI = (6.34, 11.06)

answer: r there any options?

step-by-step explanation: