Two cars, a porsche boxster and a toyota scion xb, are traveling in the same direction, although the boxster is 125.0 m behind the scion. the speed of the boxster is 26.4 m/s and the speed of the scion is 15.6 m/s. how much time does it take for the boxster to catch the scion?

t = 11.57s

The time taken for the Boxster to catch the Scion is 11.57s

Step-by-step explanation:

Given;

Speed of the boxster = 26.4m/s

Speed of the Scion = 15.6m/s

Assuming the starting point of 0 for the boxter, the starting point of the Scion would be 125.0m.

Given that;

Distance = speed × time

For the Boxster the distance travelled is;

d = 0 + 26.4t

For the scion the distance travelled is ;

d = 125 + 15.6t

Where t is the time.

Equating the two distance;

26.4t = 125 + 15.6t

26.4t - 15.6t = 125

t = 125/(26.4-15.6)

t = 11.57s

-1/2 +2

step-by-step explanation:

76%

step-by-step explanation:

24% are dogs and the remaining is 76% because 100-24=76