Find an equation of the line that passes through the point (1,-2) and is parallel to the line passing through the point (-2,-1) and (4,3)

2x - 3y = 8 is the equation of the line that passes through the point (1,-2) and is parallel to the line passing through the point (-2,-1) and (4,3)

Solution:

We have to find the equation of the line that passes through the point (1, -2) and is parallel to the line passing through the point (-2, -1) and (4, 3)

Let us first find the slope of line

We know slope of a line and slope of line parallel to it are equal

So we can find the slope of line passing thorugh the point (-2, -1) and (4, 3)

The slope of line is given as:

The points are (-2, -1) and (4, 3)

Substituting the values we get,

Thus the slope of line passing thorugh the point (-2, -1) and (4, 3) is

So the slope of line parallel to it also

Now find the equation of the line that passes through the point (1, -2) with slope

The equation of line in slope intercept form is given as:

y = mx + c ---- eqn 1

Where "m" is the slope of line and c is the y - intercept

Substitute (x, y) = (1, -2) and in eqn 1

Writing in standard form, we get

Thus the equation of line is found

45.3592

step-by-step explanation:

e) none of the above because the measure of angle cba is 101°