Suppose that there are two types of tickets to a show: advance and same-day. the combined cost of one advance ticket and one same-day ticket is $75. for one performance, 20 advance tickets and 35 same-day tickets were sold. the total amount paid for the tickets was $2100. what was the price of each kind of ticket?

The answer to your question is Advance = $35 and same-day = $40

Step-by-step explanation:

Advanced = a

Same-day = s

Equations

                       a +     s  = 75               (I)

                  20a + 35s = 2100             (II)

Process

1.- Solve the equations by elimination.

Multiply equation I by -20

                     -20a - 20s = -1500

                      20a + 35s = 2100

Simplify

                        0   + 15s = 600

Solve for s                  s = 600/15

                                    s = $ 40        

Substitute "s" in equation I to find "a"

                       a   +   40  = 75

Solve for a

                       a    = 75  - 40

                       a = 35

7 weeks

step-by-step explanation:

convert each fraction to the least common multiple of 20, so 3/4 = 15/20 & 1/10 = 2/20, then divide 15 by 2 and you get a little over 7, so the food will last 7 weeks.

50*10 is greater

step-by-step explanation:

if you add the zero from 10 to 50, it will give you a bigger number.