Pls !

 on a certain hot summer's day, 622 people used the public swimming pool. the daily prices are $ 1.75 for children and $ 2.50 for adults. the receipts for admission totaled $ 1375.00.  how many children and how many adults swam at the public pool that day? 22 points

240 children and 382 adult swam at the public pool that day

Solution:

Let "c" be the number of childrens

Let "a" be the number of adults

Cost of 1 child ticket = $ 1.75

Cost of 1 adult ticket = $ 2.50

622 people used the public swimming pool

Therefore,

number of childrens + number of adults = 622

c + a = 622 ------ eqn 1

The receipts for admission totaled $ 1375.00

Therefore, we can frame a equation as:

number of childrens x Cost of 1 child ticket + number of adults x Cost of 1 adult ticket = 1375.00

1.75c + 2.50a = 1375 ----- eqn 2

Let us solve eqn 1 and eqn 2

From eqn 1,

c = 622 - a -------- eqn 3

Substitute eqn 3 in eqn 2

1.75(622 - a) + 2.50a = 1375

1088.5 - 1.75a + 2.50a = 1375

0.75a = 1375 - 1088.5

0.75a = 286.5

a = 382

Substitute a = 382 in eqn 3

c = 622 - 382

c = 240

Thus 240 children and 382 adult swam at the public pool that day

b

step-by-step explanation:

the word superfluous means unnecessary

i got 10.28 but that rounds up to 10.3